1.

How many milligrams of bromine are present in a bottle containing 1/10 kg ?

Answer»


SOLUTION :`1 kg = 10^(6) mg :. "CONVERSION FACTOR" = ((10^(6) mg)/((1 kg))`
`1//10kg=0.1kg=((10^(6)mg))/((1kg))xx(0.1kg)=10^(5)`mg


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