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How many milliliters of 0.025 M K_2Cr_2O_7 are required to react completely with 25.0 mK of 0.20 M solution of FeSO_4 ? |
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Answer» Solution :The BALANCED chemical equation is `3Fe^(2+)+Cr_2O_7^(2-)+14H^(+)rarr6Fe^(3+)+2Cr^(3+)+7H_2O` 1 mol of `K_2Cr_2O_7 =6 " mol of "FeSO_4` Moles of `FeSO_4` PRESENT in 25.0 mL of 0.20 M solution `(0.20)/1000xx25.0 =0.005 mol` Now 6 mol of `FeSO_4` REQUIRE `K_2Cr_2O_7` = 1mol `=1/6xx0.005 = 0.000833 ` mol Let US calculate the volume of `K_2Cr_2O_7` solution containing 0.000833mol 0.025 mol of `K_2Cr_2O_7` are present in =100 mL 0.000833 mol of `K_2Cr_2O_7` are present in `=(1000xx0.000833)/(0.025)=33.3mL` |
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