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How many millilitres of 0.1 NH2 SO4 solution will be required for complete reaction with a solution containing 0.125 g of pure Na2co3B) 25.6 mL C) 26.3 mL D) 32.6 mlA) 23.6 mLPls don't spam |
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Answer» 23.6mlExplanation:No. of MOLES of Na 2 CO 3 = MolecularweightWeight = 1060.125 =0.001179 molNo. of equivalents of Na 2 CO 3 = (No. of moles)(VALENCE FACTOR) =0.001179×2=0.002358It gives number of equivalents required for complete reaction.For, H 2 SO 4 , No. of equivalents = Normality × Volume⇒0002358=0.1×V⇒V=23.58 ML⇒V=23.6 mL |
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