How many millilitres of 0.5 M H_(2)SO_(4) are needed to dissolve 0.5 g of copper (II) carbonate ?

How many millilitres of 0.5 M H_(2)SO_(4) are needed to dissolve 0.5 g

1.	How many millilitres of 0.5 M H_(2)SO_(4) are needed to dissolve 0.5 g of copper (II) carbonate ?
Answer» Solution :`N_(1)V_(1)=N_(2)V_(2)` `N_(1)= "Normality of " H_(2)SO_(4)=0.5xx2=1N` `V_(1)= " VOL of " H_(2)SO_(4)` `N_(2)`= Normality of copper (II) carbonate `=(0.5xx2)/(123.5)N` `V_(2)`=VOLUME of copper (II) carbonate =1000 ML Thus, `1.0xxV_(1)=(0.5xx2)/(123.5)xx1000` or `V_(1)=8.09 mL`