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How many mL of 0.5 N HCl acid will be required to completely neutralise 500ml of a 0.1N NaOH solution? a)50 ml b)100 ml c)150 ml d)200 ml |
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Answer» Option C is correctExplanation:First ,CALCULATE the number of moles of NAOH present in 5 grams. The molar mass of NaOH is 40 g/mol.Number of moles of NaOH in 5 GRAM = 405 =0.125 moles.The moles of HCl needed = moles of NaOHM 1 V 1 =M 2V 20.25×V 1=0.125×1000V1 =0.250.125×1000 =500 mLOption C is correct. |
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