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How many mL. of aqueous solution of `KMnO_(4)` containing `158g/L` must be used to complete the conversation of `75.0g` of `KI` to iodine by the reaction `KMnO_(4)+KI+H_(2)SO_(4)rarrK_(2)SO_(4)+MnSO_(4)+I_(2)+6H_(2)O` |
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Answer» `N_(KMnO_(4))=(158)/(31.6xx1)=5.0` M `(Mn^(7+)+5erarrMn^(2+)` `therefore E=(M)/(5)=(158)/(5)=31.6)` Meq.of `KI=(75xx1000)/(166)=451.8` `(2I^(-)rarrI_(2)+2e therfore E=(M)/(1)=(166)/(1))` Now Meq.of `KMnO_(4)="Meq.of" KI` `5xxV=45.451.8` `therefore V=90.36 mL` |
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