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How many mloes of of `AgCI` would be obtained when `100mL` of `0.1 M Co(NH_(3))_(5)CI_(3)` is treated with excess of `AgNO_(3)` ? (a) 0.01 (b) `0.02` (c ) `0.03` (d )None of these . |
Answer» Correct Answer - b `CN` of `Co^(3+) =6` . So, formula of complex and reaction are as follows `{:([Co(NH_(3))_(5)CI]CI_(2)+2underset(darr)AgNO_(3),,,,),(2AgCI+[Co(NH_(3))_(5)CI](NO_(3))_(2),,,,):}` m moles of complex `= 100mL xx 0.1 M = 10 m` moles. :. 1 m mole of complex `implies2` m moles of `AgCI` :.10m mole of complex `implies` 20m moles of `AgCI` `implies 20 xx 10^(-3) = 0.02` moles . |
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