How many mole of FeCl_(3) can be prepared by the reaction of 10g pf KMnO_(4)10.07mole of FeCl_(2) and 500mL of 3M HCl follwing the reaction: 5FeCl_(2) + KMnO_(4) + 8HCI rarr 5FeCl_(3) + KCl + MnCl_(2) + 4H_(2)O

How many mole of FeCl_(3) can be prepared by the reaction of 10g pf KM

1.	How many mole of FeCl_(3) can be prepared by the reaction of 10g pf KMnO_(4)10.07mole of FeCl_(2) and 500mL of 3M HCl follwing the reaction: 5FeCl_(2) + KMnO_(4) + 8HCI rarr 5FeCl_(3) + KCl + MnCl_(2) + 4H_(2)O
Answer» ANSWER :`0.315 MOLE`