How many molecules are present in 32 g of methane?

1.	How many molecules are present in 32 g of methane?
Answer» `2xx6.023xx10^(23)` `6.023xx10^(23)//2` `6.023xx10^(-23)` `3.011xx10^(23)` Solution :METHANE `(CH_(4))` -MOLAR mass=12+4=16g 16 g contains `6.023 xx 10^(23)` molecules. 32 g of methane will contain =`(6.022xx10^(23))/CANCEL(16)xxcancel(32^(2))=2xx6.023xx10^(23)`

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