How many molecules are present in 32 g of methane? (a) 2 x 6.023 x 10

1.	How many molecules are present in 32 g of methane? (a) 2 x 6.023 x 1023 (b) 6.023 x 1023 (c) 6.023 x 1023 (d) 3.011 x 1023
Answer» (a) 2 x 6.023 x 10²³ Methane (CH₄) – Molar mass = 12 + 4 = 16g. 16 g contains 6.023 x 10²³ molecules. ∴ 32 g of methane will contain =\(\frac{6.023\times10^{23}}{16}\) x 32² = 2 x 6.023 x 10²³

How many molecules are present in 32 g of methane? (a) 2 x 6.023 x 1023 (b) 6.023 x 1023 (c) 6.023 x 1023 (d) 3.011 x 1023

Answer»

(a) 2 x 6.023 x 10²³

Methane (CH₄) – Molar mass = 12 + 4 = 16g.

16 g contains 6.023 x 10²³ molecules.

∴ 32 g of methane will contain =\(\frac{6.023\times10^{23}}{16}\) x 32²

= 2 x 6.023 x 10²³