How many molecules of water are present in 0.9 g of water ?

1.	How many molecules of water are present in 0.9 g of water ?
Answer» Solution :No. of moles of 0.9 G of water `= (("1 mol"))/(("18.0 g"))=(0.9g)=0.05` mol No. of `H_(2)O` molecules present `= ((6.022 xx10^(23)"molecules"))/(("1.0 mol"))XX(0.01mol)` `= 3.01 xx 10^(22)` molecules.

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