How many molecules of water of hydration are present in 630mg of oxali

1.	How many molecules of water of hydration are present in 630mg of oxalic acid?
Answer» 6.0221021 Number of molecules available in oxalic acid is equal to 630 divided by 126 which come to 5.\xa0Number of molecules of water present is equal to 5 x 6.02 x 1023Therefore, number of molecules of water of hydration present in 630 mg oxalic acid is 30.1 x 10 23.\xa0

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