1.

How many molecules will be present in 64 g oxygen?

Answer»

Gram molecular weight of oxygen = 32 g
32 g of O2 contains = 6.023 × 1023 molecules
Hence, 64 g of O2 will contain 6.023 × 1023 × \(\frac{64}{32}\)
= 6.023 × 1023 × 2
= 12.046 × 1023 molecules



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