1.

How many moles and how many grams of NaCl are present in 250 ml of a 0.50 M NaCl solution?

Answer» Molarity = Moles ofsolute/Volume of solution (L)

0.50 = No . of moles of NaCl/ 250/1000

0.50 = No .of moles of Nacl/ 250 X1000

No. of moles of NaCl = 0.50 x 250/1000 = 0.125 mol

Gram molecular mass of NaCl = 23 +35.5 = 58.5 g

Mass of NaCl (g) = 0.125 x 58.5 = 7.3125 g


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