1.

How many moles H_(2) obtained from 54 gm Al. Give its reaction.

Answer»

Solution :`underset("2 mole = 54 gm")(2Al_((s))+2NaOH_((AQ)))+H_(2)O_((l))to 2NaAlO_(2(aq))+ underset("3 mole")(3H_(2(g)))`
..3 moles `H_(2)` gas obtained from 54 gm AL.


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