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How many moles H_(2) obtained from 54 gm Al. Give its reaction. |
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Answer» Solution :`underset("2 mole = 54 gm")(2Al_((s))+2NaOH_((AQ)))+H_(2)O_((l))to 2NaAlO_(2(aq))+ underset("3 mole")(3H_(2(g)))` ..3 moles `H_(2)` gas obtained from 54 gm AL. |
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