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How many moles of acidified FeSO_(4) can be completely oxidised by one mole of KMnO_(4)~ ? |
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Answer» 10 `([2FeSO_(4)+H_(2)SO_(4)+[O]toFe_(2)(SO_(4))_(3)+H_(2)O]XX5)/ul(2KMnO_(4)+10FeSO_(4)+8H_(2)SO_(4)to K_(2)SO_(4)+2KnSO_(4)+5Fe_(2)(SO_(4))_(3)+8H_(2)O)` `2" mole" KMnO_(4)-=10 " mole" FeSO_(4)` `1 "mole" KMnO_(4)-=5 " mole" FeSO_(4)` |
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