1.

How many moles of acidified FeSO_(4) can be completely oxidised by one mole of KMnO_(4)~ ?

Answer»

10
5
6
2

Solution :`2KMnO_(4)+3H_(2)SO_(4) to K_(2)SO_(4) +2MnSO_(4)+3H_(2)O +5[O]`
`([2FeSO_(4)+H_(2)SO_(4)+[O]toFe_(2)(SO_(4))_(3)+H_(2)O]XX5)/ul(2KMnO_(4)+10FeSO_(4)+8H_(2)SO_(4)to K_(2)SO_(4)+2KnSO_(4)+5Fe_(2)(SO_(4))_(3)+8H_(2)O)`
`2" mole" KMnO_(4)-=10 " mole" FeSO_(4)`
`1 "mole" KMnO_(4)-=5 " mole" FeSO_(4)`


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