1.

How many moles of acidified permanganate are required to oxidise one mole of ferrous oxalate?

Answer»

Solution :Ferrous oxalate `FeC_(2)O_(4)` is a DUAL REDUCTANT
`Fe^(2+)overset(1E^(-))rarr Fe^(3+)" "C_(2)O_(4)^(2-)overset(2e^(-))rarr2CO_(2)`
ONE mole of `FeC_(2)O_(4)` is involved in 3 electron change
`MnO_(4)^(2-) overset(5e^(-))rarr Mn^(2+)`
One mole of `MnO_(4)^(-)` in acid medium is involved in 5 electron change
5 moles of `FeC_(2)O_(4) = 3` moles of `MnO_(4)^(-)`
1 mole of `FeC_(2)O_(4) = ?`
Number of moles of permanganate that can be oxidised by one mole of ferrous oxalate `=(3)/(5)xx1=0.6`


Discussion

No Comment Found