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How many moles of acidified permanganate are required to oxidise one mole of ferrous oxalate? |
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Answer» Solution :Ferrous oxalate `FeC_(2)O_(4)` is a DUAL REDUCTANT `Fe^(2+)overset(1E^(-))rarr Fe^(3+)" "C_(2)O_(4)^(2-)overset(2e^(-))rarr2CO_(2)` ONE mole of `FeC_(2)O_(4)` is involved in 3 electron change `MnO_(4)^(2-) overset(5e^(-))rarr Mn^(2+)` One mole of `MnO_(4)^(-)` in acid medium is involved in 5 electron change 5 moles of `FeC_(2)O_(4) = 3` moles of `MnO_(4)^(-)` 1 mole of `FeC_(2)O_(4) = ?` Number of moles of permanganate that can be oxidised by one mole of ferrous oxalate `=(3)/(5)xx1=0.6` |
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