How many moles of AgBr (K_(sp)=5xx10^(-13)"mol"^(2)L^(-2)) will dissolve in 0.01 M NaBr solution ?

How many moles of AgBr (K_(sp)=5xx10^(-13)"mol"^(2)L^(-2)) will dissol

1.	How many moles of AgBr (K_(sp)=5xx10^(-13)"mol"^(2)L^(-2)) will dissolve in 0.01 M NaBr solution ?
Answer» Solution :SUPPOSE solubilityof AgBr in 0.01 M NABR = s mol `L^(-1)`. Then as `AgBr rarr Ag^(+) + Br^(-)`, `[Ag^(+)]=s"mol " L^(-1) and "Tota" [Br^(-)]=0.01 + s ~~ 0.01 M` `K_(sp) = [ Ag^(+)][Br^(-)], i.e., 5xx10^(-13)= s xx0.01 or s = 5 xx 10^(-11) "mol" L^(-1)`