1.

How many moles of calcium carbonate are in 63.8g of calcium carbonate

Answer»

0.638 moles in 63.8g of CALCIUM carbonate

Explanation:

ACCORDING to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and CONTAINS avogadro's NUMBER 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

given mass of calcium carbonate = 63.8 g

Molar mass of calcium carbonate = 100 g/mol

\text{Number of moles}=\frac{63.8g}{100g/mol}=0.638moles

Thus there are 0.638 moles in 63.8g of calcium carbonate

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