How many moles of ethane is equaired to produce 44 g of CO_(2(g)) afte

1.	How many moles of ethane is equaired to produce 44 g of CO_(2(g)) after combustion.
Answer» Solution :`UNDERSET("ETHANE")(C_(2)H_(6)) + 3xx1/2 O_(2) to underset("Carbon DIOXIDE")(2CO_(2))+3H_(2)O` 1 mole of Ethane `overset("COMBUSTION")(to)` 2 moles of `CO_(2)` `:.` 1 mole of `CO_(2)` 2 moles of `CO_(2)` is produced by 1 mole of ethane. 1 mole of `CO_(2)` will be produced by = ? `:.`To produce 1 mole of `CO_(2)` , the required mole of ethane is =`1/2 xx 1` = 0.5 mole of ethane.

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