1.

How many moles of glucose are present in 720 g of glucose ?

Answer»

SOLUTION :GLUCOSE = `C_(6)H_(12)O_(6)`
Molecular MASS of Glucose =`(12xx6)+(1xx12)+(16xx6)`
72+12+96=180
Number of MOLES of Glucose =` ("Mass of Glucose")/(" Molecular mass of Glucose")`
`720/180 = 4 `moles


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