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How many moles of glucose are present in 720 g of glucose ? |
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Answer» SOLUTION :GLUCOSE = `C_(6)H_(12)O_(6)` Molecular MASS of Glucose =`(12xx6)+(1xx12)+(16xx6)` 72+12+96=180 Number of MOLES of Glucose =` ("Mass of Glucose")/(" Molecular mass of Glucose")` `720/180 = 4 `moles |
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