How many moles of glucose are present in 720 g of glucose? – InterviewSolution

1.

How many moles of glucose are present in 720 g of glucose?

Answer»

Glucose = C₆H₄O₄

Molecular mass of Glucose = (12 x 6) + (1 x 12) + (16 x 6)

= 72 + 12 + 96 = 180

= 720/180

= 4 moles.

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