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How many moles of gold are present in 49.25 g of gold rod ? (Atomic mass of gold = 197) |
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Answer» 197.0 g of gold have mass = 1 gramk mol 49.25 g of gold have mass `= ((49.25g))/((197.0g))XX("1 gram mol")=0.25` gram mol = 0.25 mol |
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