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How many moles of gold are present in `49.25 g` of gold rod ? (Atomic mass of gold = 197)

Answer» Correct Answer - 0.25 mol
Gram atomic mass of gold `= 197.0 g`
197.0 g of gold have mass = 1 gramk mol
49.25 g of gold have mass `= ((49.25g))/((197.0g))xx("1 gram mol")=0.25` gram mol = 0.25 mol


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