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How many moles of iodine are liberated when 1 mole of potassium dichromate react with excess of potassium iodide in the presence of concentrated sulphuric acid ?

Answer»

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Solution :`K_(2)Cr_(2)O_(7)+6Kl+7H_(2)SO_(4)rarr4K_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+7H_(2)O+3l_(2)`


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