1.

How many moles of KMnO_(4) required to oxidised acidic medium of 1 mole Fe(C_(2)O_(4)) ?

Answer»

0.6
1.67
0.2
0.4

Solution :`MnO_(4)^(-)+8H^(+)+5e^(-)toMn^(+2)+4H_(2)O`
`FE^(+2)+C_(2)O_(4)^(-2)toFe^(+3)+2CO_(2)+3e^(-)`
`therefore` Moles of `KMnO_(4)` REQUIRED to oxidised 1 mole `Fe(C_(2)O_(4))=3/5=0.6`


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