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How many moles of KMnO_4are needed to oxidised a mixture of 1 mole of each FeSO_4" & "FeC_(2)O_4in acidic medium |
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Answer» `4//5 ` 10MOLES g `FesO_4` requires 2 MOLES of `KMnO_4` 1 MOLE of `FeC_(2)O_4` require = 1/5 moles of `KMnO_4` `6KMnO(4) +10FeC_(2)O_(4)+24H_(2)SO_(4) rarr 3K_2SO_(4) + 6MnSO_(4) +5Fe_(2)(SO_4)_(3)+20CO_(2)+24H_(2)O` 10 mole of `FeC_(2)O_(4)` require = 6 mole of `KMnO_4` 1 mole of `FeC_(2)O_4 ` requires `=6/10 =3/5` Total moles of `KMnO_(4) ` require `=1/5+3/5 =4/5` |
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