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How many moles of magnesium phosphate Mg_3 (PO_4)_2 will contain 0.25 mole of oxygen atoms ? |
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Answer» (a) `0.02` `therefore` 0.25 moles of oxygen atoms will be present in`1/8 xx 0.25 = 3.125 xx 10^(-2)` moles of `Mg_(3)(PO_(4))_(2)`. |
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