1.

How many moles of magnesium phosphate Mg_3 (PO_4)_2 will contain 0.25 mole of oxygen atoms ?

Answer»

(a) `0.02`
(b) `3.125 xx 10^(-2)`
(C) `1.25 xx 10^(-2)`
(d) `2.5 xx 10^(-2)`

Solution :From the formula, `Mg_3(PO_4)_2`, it .s clear that 8 moles of oxygen atoms are present in 1 mole of MAGNESIUM phosphate.
`therefore` 0.25 moles of oxygen atoms will be present in`1/8 xx 0.25 = 3.125 xx 10^(-2)` moles of `Mg_(3)(PO_(4))_(2)`.


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