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How many moles of magnesium phosphate` Mg _(3)(PO_(4))_(2)` will contain 0.25 mole of oxygen atoms ?A. `2.5xx10^(-2)`B. 0.02C. `3.125xx10^(-2)`D. `1.25xx10^(-2)` |
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Answer» Correct Answer - C 8 mole O contained by `to 1 "mole" Mg_(3)(PO(4)_(3))` 1 mole O contained `(1)/(8) "mole" Mg_(3)(PO(4)_(2))` by 0.25 "mole" O is ` rArr (1)/(8)xx0.25` "mole" `Mg_(3)(PO(4))_(3)` contained by ` = 3.125 xx10^(-2)` mole `Mg_(3)` |
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