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How many moles of magnesium phosphate, `Mg_(3)(PO_(4))_(2)` will contain 0.25 mole of oxygen atoms ?A. 0.02B. `3.125 xx 10^(-2)`C. `1.25 xx 10^(-2)`D. `2.5 xx 10^(-2)` |
Answer» Correct Answer - B `underset("1 mole")(Mg_(3)(PO_(4))_(2))-=underset("8 mole")(8(O))` 8 mole of oxygen atoms are present in `Mg_(3)(PO_(4))_(2)=1` mole 0.25 mole of oxygen atoms are present in `Mg_(3)(PO_(4))_(2)` `=(1xx0.25)/(8)=3.125xx10^(-2)` mole. |
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