How many moles of methane are required to produce 22 g CO_(2)(g) after

1.	How many moles of methane are required to produce 22 g CO_(2)(g) after combustion ?
Answer» Solution :ACCORDING to the chemical EQUATION, `CH_(4(g)) +2O_(2(g)) rarr CO_(2(g)) + 2H_(2)O_((g))` 44 g `CO_(2(g))` is obtained from 16 g `CH_(4(g))` ( `:.` 1 mol `CO_(2(g))` is obtained from 1 mol of `CH_(4(g))` ) Mole of `CO_(2(g)) = 22 g CO_(2(g)) XX ("1 mol" CO_(2(g)))/(44 g CO_(2(g)))` `= 0.5 "mol" CO_(2(g))` Hence, 0.5 mol `CO_(2(g))` would be obtained from 0.5 mol `CH_(4(g))` or 0.5 mol of `CH_(4(g))` would be required to PRODUCE 22 g `CO_(2(g))`.

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