How many moles of Mg_(3)(PO_(4))_(2) consists 0.25 mole oxygen atoms ?

1.	How many moles of Mg_(3)(PO_(4))_(2) consists 0.25 mole oxygen atoms ?
Answer» `2.55xx10^(-2)` `0.0225` `3.125xx10^(-2)` `1.5xx10^(-2)` SOLUTION :1 mole `Mg_(3)(PO_(4))_(2)` consists 8 mole .O. atoms 8 mole atoms in 1 mole `Mg_(3)(PO_(4))_(2)` `:.0.25` mole atoms `= (?)` `=(0.25xx1)/(8) = 0.03125 = 3.125xx10^(-2)` mole

Discussion