How many moles of P_(4) can be produced by reaction of 0.1 mole Ca_(5)(PO_(4))_(3)F,0.36 mole SiO_(2) and 0.90 mole C according to the following reaction? 4Ca_(5)(PO_(4))_(3)F+18SiO_(2)+30Crarr3P_(4)+2CaF_(2)+18CaSiO_(3)+30CO

How many moles of P_(4) can be produced by reaction of 0.1 mole Ca_(5)

1.	How many moles of P_(4) can be produced by reaction of 0.1 mole Ca_(5)(PO_(4))_(3)F,0.36 mole SiO_(2) and 0.90 mole C according to the following reaction? 4Ca_(5)(PO_(4))_(3)F+18SiO_(2)+30Crarr3P_(4)+2CaF_(2)+18CaSiO_(3)+30CO
Answer» `0.060` `0.030` `0.045` `0.075` Solution :`4Ca_(5)(PO_(4))_(3)F+18SiO_(2)+30C` `{:((0.1)/(4),(0.36)/(18),(0.9)/(30)),(=0.025,0.02,0.03):}` `THEREFORE SiO_(2)` is the LR `18SiO_(2)rarr3P_(4)implies0.36rarr0.06P_(4)`