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How many moles of Pr may be deposited on the cathode when 0.80F of electricity is passed through 1.0M solution of `Pt^(4+)`?A. 0.1 molB. 0.2 molC. 0.4 molD. 0.6 mol |
Answer» Correct Answer - B `Pt^(4+) + 4e^(-) to Pt` 4 moles of electricity or 4 F of electricity is required to deposit 1 mole of Pt. 0.80 F of electricity will deposit `1/4xx0.80` =0.20 mol |
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