How many moles of solute are required in 300 g solvent to prepare 3 mo

1.	How many moles of solute are required in 300 g solvent to prepare 3 molal solution ?
Answer» 0.01 1 0.09 0.9 Solution :`=("weight of solute (GM)")/("molecular mass " xx "WT. of solvent in kg")` ` 3 = ("MOLE")/("weight of solvent")` `= ("MALE")/(0.300)` Mole `= 3 xx 0.3 = 0.9`

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