How many number of P, O and H respectively on L.H.S. and R.H.S in following redox reaction after balanced ? P_(4)+OH^(-)toPH_(3)+H_(2)PO_(2)^(-)

How many number of P, O and H respectively on L.H.S. and R.H.S in foll

1.	How many number of P, O and H respectively on L.H.S. and R.H.S in following redox reaction after balanced ? P_(4)+OH^(-)toPH_(3)+H_(2)PO_(2)^(-)
Answer» P = 16, O = 12, H = 34 P = 4, O = 3, H = 3 P = 4, O = 6, H = 9 P = 4, 0 = 6, H = 6 Solution :(i) `underset((0))(P_(4))+OH^(-)tounderset((-3))(PH_(3))+underset((+1))(H_(2)PO_(2)^(-))` (ii) `underset("Increase of "(4)xx1)(underset((0))(P_(4))+underset((0))(P_(4))+OH^(-)tounderset((-12))(4PH_(3))+underset((+4))(4H_(2)PO_(2)^(-)))` (iii) `underset("DECREASE of "(12)xx1)(underset((0))(P_(4))+underset((0))(P_(4))+OH^(-)tounderset((-12))(4PH_(3))+underset((+4))(4H_(2)PO_(2)^(-)))` (iv) `P_(4)+3P_(4)+OH^(-)to4PH_(3)+12H_(2)PO_(2)^(-)` (v) `4P_(4)+12OH^(-)+12H_(2)Oto4PH_(3)+12H_(2)PO_(2)^(-)` `P_(4)+3OH^(-)+3H_(2)OtoPH_(3)+3H_(2)PO_(2)^(-)`