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How many numbers of three digits can be formed with digits 1, 3, 5, 7 and 9?(a) 983(b) 120(c) 345(d) 5430The question was asked during an internship interview.This intriguing question originated from Counting in chapter Counting of Discrete Mathematics

Answer»

Correct option is (B) 120

The EXPLANATION is: Here number of digits, n = 5 and number of places to be filled-up R = 3. Hence, the required number is ^5P3 = 5!/2!*3! = 120.



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