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How many orders will be visible if the wavelength of incident radiation is 5000 nm and the number of lines on the grating is 2620 per inch? |
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Answer» Given : d = \(\cfrac1{2620}\) per inch d = \(\cfrac{1}{\cfrac{2620}{0.0284}}\) d = \(\cfrac1{10314}\) per meter. using n\(\lambda\) = d sin θ θ = 90° n\(\lambda\) = d n = \(\cfrac d{\lambda}\) n = \(\cfrac1{5000\times10^{-9}\times10314}\) n = \(\cfrac{1000000}{51570}\) n = 19.39 |
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