How many oxygen atoms are present in 2.2 mg of CO2?

1.	How many oxygen atoms are present in 2.2 mg of CO2?
Answer» Mass=2.2mg ,moles of (CO2)=mass÷molarmass = 2.2÷44 ×100=5(CO2) mol. 5mol of Co2=5 na molecules 44g CO2 contains 6.022×10^23 molecules of CO2=6.022×10^23 atoms of C + 12.044×10^23 O atomsTherefore 44g CO2 = 12.044×10^23 O atoms.Now, 1g CO2 contains 12.044×10^23/44 O atomsSo 2.2×10^-3g CO2 contains (12.044×10^23/44)×2.2×10^-3=11.022×10^19 O atoms. I hope it\'s clear

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