1.

How many oxygen atoms are present in 22g of CO2 ?? ☺☺☺

Answer»

First you NEED to find relative molecular mass. You can calculate it USING relative atomic mass of C and O So

MCO2=12+16×2

=44gmol−1

molecular mass of CO2 is 44. Which mean 44 grams of CO2contain Avogadro’s number of ATOMS. So,

44gmol−1=6.022×1023mol−1(Avogadro’s number)

442=6.022×10232

22G=3.011×1023

So 22g of CO2have 3.011×1023 CO2molecules.

Since ONE molecule has one carbon atom it also has 3.011×1023 Carbon atoms


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