How many oxygen atoms are there Ba3(PO4)2 in 6.025g (Ba=137,P=31)

1.	How many oxygen atoms are there Ba3(PO4)2 in 6.025g (Ba=137,P=31)
Answer» Barium phosphate (at. mass of Ba=137.5, P= 31, O = 16 amu) ... Sol 3: Barium phosphate = BA3(PO4)2.4 OXYGEN atomsKindly mark me as brainliest...plzzzhope u like my answer..

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