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How many positive divisors does 4000 = 2^5 5^3 have?(a) 49(b) 73(c) 65(d) 15The question was asked in exam.My question comes from Multiplication Theorem on Probability topic in portion Discrete Probability of Discrete Mathematics

Answer»

Correct CHOICE is (d) 15

Explanation: Any positive DIVISOR of 4000 must be of the form 2^x5^y, where x and y are integers satisfying o<=x<=5 and 0<=y<=3. There are 5 POSSIBILITIES for x and 3 possibilities for y and HENCE there are 3*5 = 15(rule of product) positive divisors of 4000.



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