1.

How many positive integers greater than 5,000,000 can be formed using the digits 2, 3, 3, 5, 5, 6, 8?

Answer»

If 1st digit number starts with 5, 6 and 8 then all formed numbers by using given digits are greater than 5000000.

case I: If number starts with digit 5

5

Possible numbers  = 6!/2! = 720/2 = 360

Case II: If number starts with digit 6

6

Possible numbers = 6!/2!2! = 720/4 = 180

Case III: If number starts with digit 8

8

possible numbers = 6!/2!2! = 720/4 = 180


\(\therefore\) Total number of positive integers which is greater than 5000000 and formed by using digits 2,3,3,5,5,6,8 

= 360 + 180 + 180 = 720



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