Saved Bookmarks
| 1. |
How many positive integers greater than 5,000,000 can be formed using the digits 2, 3, 3, 5, 5, 6, 8? |
|||||||||||||||||||||
|
Answer» If 1st digit number starts with 5, 6 and 8 then all formed numbers by using given digits are greater than 5000000. case I: If number starts with digit 5
Possible numbers = 6!/2! = 720/2 = 360 Case II: If number starts with digit 6
Possible numbers = 6!/2!2! = 720/4 = 180 Case III: If number starts with digit 8
possible numbers = 6!/2!2! = 720/4 = 180
= 360 + 180 + 180 = 720 |
||||||||||||||||||||||