1.

How many positive integers less than 1000 are 6 times the sum of their digits?     (a) 0 (b) 1 (c) 2 (d) 3

Answer»

Answer: B. 

Number less than 1000 can write 

abc =100a + 10b  +c

 where a, b, c ∈  {0,1 2 3....... 9 }  and a+b+c > 0

 The sum of digits of this number is ( a+b+c).

. Given, 100a+10b+c= 6 (a+b+c)

∴ 94a+ 4b -5c = 0

 Clearly, a > 0. No solution 

∴  a = 0 then 4b = 5c 

 This is possible only 

b = 5 and c = 4 

∴Number is 54.

 Hence, only one number i.e., 54.



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