How many protons are present in 4 g NaOH ?

1.	How many protons are present in 4 g NaOH ?
Answer» `6.022xx10^(23)` `12.044xx10^(23)` `12.044xx10^(24)` `6.022xx10^(22)` Solution :(i) Molecular mass of NaOH `= 23 + 16 +1` `= 40 g*MOL^(-1)` (ii) Mole `= ("weight")/("molecular weight")` `= (4.0)/(40.0) = 0.1` mole NaOH (iii) NaOH =`(""_(11)Na + ""_(8)O +""_(1)H)` TOTAL no. of proton `=20` in each molecule of NaOH (iv) Thus one mole of NaOH have `20 xx 6.022 xx 10^(23)` total protons. `:.0.1`one mole of NaOH have (?) protons `=0.1xx20xx6.022xx10^(23)` `= 12.044 xx10^(23)` protons

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