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How many sigma and pi bonds are present in each of the following molecules? (a) HC -= C CH= CHCH_(3) (b) CH_(2) = C = CHCH_(3) |
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Answer» Solution :(a) `H underset(sigma)- C underset(sigma)(-=) C - underset(underset(H)(|))(C )= overset(overset(H)(|))(C )- underset(underset(H)(|))overset(overset(H)(|))(C )-H` `H overset(sigma)- C underset(sigma)overset(2pi)(-=) C overset(sigma)- underset(underset(H)(sigma|))(C ) underset(pi)overset(sigma)= underset(underset(H)(sigma|))(C )- underset(underset(H)(sigma|))overset(overset(H)(sigma|))(C )overset(sigma)- H` `{:(pi "bond": C -= C,: "two " pi "bond"),(C= C,: "one " pi "bond"),(,BAR("Total three " pi "bond")):}` `sigma` bond " `6C - H sigma + 4 C-C sigma` `:. 10 sigma` bond In Acyclic hydrocarbon `C-C sigma` bond = (Total CARBON -1) `C-H sigma` bond = (No. of total - H) No. of `pi` bond = (No. of tripal `xx 2`) = (No.of double bond `xx1` ) No. of `pi` bond `= (("No. H atom according to No. formaula of alkane")-("No. of PRESENT molecule"))/(2)` (B) `CH_(2)= C = CH - CH_(3)` Formula: `C_(4)H_(6)` So, with `6H 6C- H sigma` bond + between 4 carbon `(4-1)= 3 sigma` bond `:. bar("total " 9 sigma"bond ")`  + two `pi` bond (becasue of two double bond) |
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