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How many six digit numbers can be formed using all the digits 1, 2, 3, 0, 7, 9? |
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Answer» Using all the digits 1, 2, 3, 0, 7, 9, six digit numbers are to be formed. Now, remaining 5 digits (including 0) can be arranged in remaining 5 places in 5P5 ways. ∴ Total permutations for six digit numbers = 5P1 × 5P5 = 5 × 5! = 5 × 120 = 600 Hence, 600 numbers of 6 digit can be formed. |
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