1.

How many six digit numbers can be formed using all the digits 1, 2, 3, 0, 7, 9?

Answer»

Using all the digits 1, 2, 3, 0, 7, 9, six digit numbers are to be formed.
∴ Excluding digit 0, one of the five digits can be placed at the first place in 5P1 ways

Now, remaining 5 digits (including 0) can be arranged in remaining 5 places in 5P5 ways.

∴ Total permutations for six digit numbers

5P1 × 5P5

= 5 × 5!

= 5 × 120

= 600

Hence, 600 numbers of 6 digit can be formed.



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