How many sulphur atoms present in 2N 500 mL of sulphuric acid ? (At. Mass of H = 1, S = 32, O = 16 gms/mole)

How many sulphur atoms present in 2N 500 mL of sulphuric acid ? (At.

1.	How many sulphur atoms present in 2N 500 mL of sulphuric acid ? (At. Mass of H = 1, S = 32, O = 16 gms/mole)
Answer» `1.515xx10^(23)` `6.022xx10^(23)` `1.5057xx10^(22)` `3.0115xx10^(23)` Solution :2N 500 mL `H_(2)SO_(4)` solution Normality (N ) `=("wt. of solute" xx 1000)/("EQ. wt. of solute" xx "Vol of solution")` `:.2 = (x xx1000)/(149xx500)` `:.x=49g` `:.` wt of `H_(2)SO_(4) = 49 g` Moles of `H_(2)SO_(4) = 0.5` moles No. of molecules in 0.5 moles of `H_(2)SO_(4)` `=0.5xx6.022xx10^(23)` `= 3.011xx10^(23)` As `H_(2)SO_(4)` contains one sulphur atom No. of sulphur atoms `= 3.011xx10^(23)xx1` `= 3.011 xx10^(23)` atoms