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How many terms of the G.P. 1,4,16 ..... must be taken to have their sum equal. |
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Answer» Sn = 3 + 32 +33 +..... = \(\frac{3(3^n-1)}{3-1}=\frac32(3^n-1)\) S'n= 1 + 7 + 16 + .. = 40 + 41 + 42+..... = \(\frac{4^0(h^n-1)}{4-1}\) = \(\frac{4^n-1}3\) |
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