1.

How many times the normal electrons of hydrogen atom revolve round the nucleus in on sec ?

Answer»

SOLUTION :`"NUMBER of revolutions "=("velocity of the electron ")/("circumference of shell")`
For hydrogen electron in `n=1`, Velocity `= 2.18xx 10^(6) ms^(-1)`
`" Circumference of shell "= 2pir`
`2pixx0.529xx10^(-10)xxn^(2)m`
`=2xx3.14xx0.529xx10^(-10)xx1^(2)=3.33xx10^(-10)m`
`"Number of times the electrons revolve in one sec "= 2`
`(2.18xx10^(6))/(3.33xx10^(-10))=6.55xx10^(15)s^(-1)`.


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