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How many times the normal electrons of hydrogen atom revolve round the nucleus in on sec ? |
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Answer» SOLUTION :`"NUMBER of revolutions "=("velocity of the electron ")/("circumference of shell")` For hydrogen electron in `n=1`, Velocity `= 2.18xx 10^(6) ms^(-1)` `" Circumference of shell "= 2pir` `2pixx0.529xx10^(-10)xxn^(2)m` `=2xx3.14xx0.529xx10^(-10)xx1^(2)=3.33xx10^(-10)m` `"Number of times the electrons revolve in one sec "= 2` `(2.18xx10^(6))/(3.33xx10^(-10))=6.55xx10^(15)s^(-1)`. |
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